This may have been answered before. I see many "dynamic method overload resolution" questions, but none that deal specifically with passing a dynamic
argument. In the following code, in Test
, the last call to M
cannot be resolved (it doesn't compile). The error is: the call is ambiguous between [the first two overloads of M
].
static void M(Func<int> f) { }
static void M(Func<string> f) { }
static void M(Func<开发者_运维技巧dynamic> f) { }
static dynamic DynamicObject() {
return new object();
}
static void Test() {
M(() => 0);
M(() => "");
M(() => DynamicObject()); //doesn't compile
}
- Why, since the type isn't statically known, does it not resolve to the overload accepting
dynamic
? - Is it even possible for an overloaded method to use
dynamic
? - What is the best way to resolve this?
The problem here is type inference. The compiler is trying to find out which overload to use based on the argument, but it's also trying to find out what the type of the argument is based on the chosen overload. In the case of M(() => DynamicObject())
, the process goes something like this:
- The argument to the method is a lambda with zero parameters. This gives us all three overloads as possibilities.
- The body of the lambda returns
dynamic
. Because there is an implicit conversion fromdynamic
to any other type, we now know all three overloads are good. - Try choosing the best overload. In most cases, “best” means the most derived type. Because both
int
andstring
derive fromobject
, the overloads withint
andstring
are considered best. - We now have two “best” overloads, which means the compiler can't actually choose one of them. The compilation fails.
Now, regarding possible solutions to your problem:
Make the type of the lambda explicit, either using cast or typed local variable:
M((Func<dynamic>)(() => DynamicObject()));
or
Func<dynamic> f = () => DynamicObject(); M(f);
Rename the dynamic overload to something like
DynamicM
. This way, you don't have to deal with overload resolution.This one feels somewhat wrong to me: make sure the
dynamic
overload is the only one that fits, by casting toobject
:M(() => (object)DynamicObject())
From the definition in MSDN:
dynamic
Type dynamic behaves like type object in most circumstances. However, operations that contain expressions of type dynamic are not resolved or type checked by the compiler. The compiler packages together information about the operation, and that information is later used to evaluate the operation at run time. As part of the process, variables of type dynamic are compiled into variables of type object. Therefore, type dynamic exists only at compile time, not at run time
So dynamic doesn't exist when you compile, cause it needs to convert it into destination *type*, and that's why is not able to resolve it. What is destination type ?
In fact if you do something like this:
static void M(Func<int> f) { }
static void M(Func<string> f) { }
static void M(Func<object> f) { } // could be also declared like dynamic here, works by the way
static object DynamicObject()
{
return new object();
}
static void Test()
{
M(() => 0);
M(() => "");
M(() => DynamicObject());
}
It perfectly works as you want, as object
is present like a type already at compile time, in difference of dynamic
type which have to be converted.
精彩评论