I have 2 lists and am a little confused about adding an object into both of them like this:
TestClass e;
List lst1;
LinkedList lst2;
...
lst1.add(e);
lst2.add(e);
Will 开发者_StackOverflow中文版lst1
and lst2
have copies of e
? or the reference to the same object e
?
e
if TestClass
is not clonable?They will have the same reference. You will have to manually copy values over if you want it to be 2 distinct properties.
The second is true: both collections will hold a reference to that same object.
Will
lst1
andlst2
have copies ofe
?
Yes.
Both lists will have a copy of the value contained in e
. (Note though, that e
contains a reference and not an actual object.)
This means that
Both lists will have one copy each of the reference to the
TestClass
object whiche
refers to at the point of theadd
.Changes to the
TestClass
object will be visible from both lists references.Performing
e = null
after the add will not affect the content of the lists (the lists contain copies, remember? ;-)
This goes back to the old question of passing by reference vs passing by value...
See this stackoverflow question
Both lst1
and lst2
will contain a value (represented by the variable e
) that will tell the JVM how to find the TestClass
instance in the Heap Memory. If you modify the instance (there is only one instance) by accessing it through e
, lst1
, or lst2
the changes will be visible everywhere!
The only way to change this behavior is to override the Object clone()
in TestClass
function and passing e.clone()
to the add(...)
function. Please refers to the documentation
If you cannot modify the TestClass
for any reasons you can also clone the instance by yourself (basically you implement clone()
outside TestClass
). Create a new TestClass
instance e2
with the new
operator and then get its instance variables (be careful is it contains other custom objects) from e
through its 'getters' and set the values to e2
through its 'setters'. This is ugly as hell and I hope you refuse to do it...
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