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Javascript XMLHttpRequest Invalid Argument

开发者 https://www.devze.com 2023-03-30 18:45 出处:网络
I\'m 开发者_运维知识库currently working on a project trying to update a page reading from an XML file on our intranet server.After doing some working I came up with the following code:

I'm 开发者_运维知识库currently working on a project trying to update a page reading from an XML file on our intranet server. After doing some working I came up with the following code:

// IE7+
if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); }
// IE6, IE5
else { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); }
xmlhttp.open("GET", "VerifiedUrl+XML.xml", false);
xmlhttp.send();
xmlDoc = xmlhttp.responseXML;
if (xmlDoc.getElementsByTagName("CheckBox")[0].childNodes[0].nodeValue == "True"){
    document.getElementById("PartToUpdate").innerHTML = xmlDoc.getElementsByTagName("TextBox")[0].childNodes[0].nodeValue;
}

Now I've tested this code on my localhost and it does in fact read from the correct file, displaying the updated information, but when I deploy it to the intranet, I get an "Invalid Argument" error. (The XML file itself has been deployed and is referencing correctly).

Edit: I've recently found the problem, in that the path I was referencing apparently couldn't find the file itself. So that brings up another question that someone might be able to shed light on:

//When referencing a file within the same folder, it works correctly.  
xmlhttp.open("GET", "Sample.xml", false);

//However, if I include the full path, it doesn't read correctly.  (Double slashes to escape correctly)
xmlhttp.open("GET", "\\\\Full\\Server\\Path\\Here\\Sample.xml", false);  

Perhaps someone could shed some light on this?


should your path be something like this:

xmlhttp.open("GET","./Path/Here/books.xml", false);  //for relative urls

xmlhttp.open("GET","http://localhost/Path/Here/books.xml", false); //for absolute urls

and if its a non-http synchronous request

var request = new XMLHttpRequest();

request.open('GET', 'file:///home/user/file.json', false);

its not similar to your system path.


The path here is wrong:

 xmlhttp.open("GET", "\\\\Full\\Server\\Path\\Here\\Sample.xml", false);  

You are using the wrong type of slashes for the internet, they would be correct on a file system. It needs to use a forward slash.

xmlhttp.open("GET", "//Full/Server/Path/Here/Sample.xml", false);  


Have you checked the same-origin policy?

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