I am currently using jQuery .click() method to update 15 text fields with simple color hex values i.e. like this document.form1.top_menu_bgcolor.value = '#FFFFFF';
I am also using ExColor for jQuery http://modcoder.org/ to display a killer color picker http://modcoder.org/js/modcoder-1.1.js
The problem is that when you click to update the fields, the color picker swatches don't get refreshed.
How can I simply reactivate or refresh the swatches when the fields are changed? What can I call in the .click function below to refresh the swatches to the new hex string, input value?
开发者_如何学GoHere's the JS:
<script type="text/javascript">
$('document').ready(function() {
// running ExColor
$('#my_input_1').modcoder_excolor();
$('#my_input_2').modcoder_excolor();
$('#my_input_3').modcoder_excolor();
$('#my_input_4').modcoder_excolor();
$('#my_input_5').modcoder_excolor();
$('#my_input_6').modcoder_excolor();
$('#my_input_7').modcoder_excolor();
$('#my_input_8').modcoder_excolor();
$('#my_input_9').modcoder_excolor();
$('#my_input_10').modcoder_excolor();
$('#my_input_11').modcoder_excolor();
$('#my_input_12').modcoder_excolor();
$('#my_input_13').modcoder_excolor();
$('#my_input_14').modcoder_excolor();
$('#my_input_15').modcoder_excolor();
$('#theme01').click(function() {
document.form1.top_menu_bgcolor.value = '#FFFFFF';
document.form1.top_menu_bgcolor.focus();
document.form1.top_menu_fontcolor.value = '#FFFFFF';
document.form1.top_menu_bghovercolor.value = '#FFFFFF';
document.form1.top_menu_fonthovercolor.value = '#FFFFFF';
document.form1.left_menu_bgcolor.value = '#FFFFFF';
document.form1.left_menu_fontcolor.value = '#FFFFFF';
document.form1.left_menu_bghovercolor.value = '#FFFFFF';
document.form1.left_menu_fonthovercolor.value = '#FFFFFF';
document.form1.left_div_border.value = '#FFFFFF';
document.form1.site_background_color.value = '#FFFFFF';
document.form1.header_color.value = '#FFFFFF';
document.form1.content_header_color.value = '#FFFFFF';
document.form1.browser_bg_color.value = '#FFFFFF';
document.form1.footer_color.value = '#FFFFFF';
document.form1.footer_font_color.value = '#FFFFFF';
});
</script>
And the HTML
<a href="#" id="theme01">Theme 1</a>
<input type="text" ID="my_input_1" name="top_menu_bgcolor" maxlength="7" value="#000000" size="10" />
You can try using something similar to:
<script type="application/javascript">
$(document).ready(function(){
$("#theme01").click(function(){
$("#myinput1").val('#aaafFF');
$('#myinput1').click();
setTimeout( function(){
$('#c3').blur();
$('#c3').click();
$('#c3').blur();},
50);
return false;
});
});
</script>
where #c3 is a different div somewhere.
This will in effect, show and hide the modcoder fast enough the user does not see it.
Edit: Full Answer
$("#theme01").click(function(){
$("#myinput1").val('#aaaFFF');
$('#myinput1').click();
setTimeout( function(){$('#modcoder_ok').click();}, 50);
});
$("#theme02").click(function(){
$("#myinput1").val('#222ccc');
$('#myinput1').click();
setTimeout( function(){$('#modcoder_ok').click();}, 50);
});
And then in html: Theme 1 Theme 2
I use two buttons, the delayed #modcode_ok.click() does a programmatically click of the ok button to select and refresh the color. On my computer the setTimeout at 50ms is too fast and I cannot see the popup. Maybe you need to adjust on your needs.
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