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Pass viewmodel to ajax controller action that returns partial with that model?

开发者 https://www.devze.com 2023-03-30 11:13 出处:网络
I have a view that is strongly typed. Inside this view i have jqueryui tabs, that when clicked call my Controller and return a partial view

I have a view that is strongly typed. Inside this view i have jqueryui tabs, that when clicked call my Controller and return a partial view

("#tab0").load('@Url.Action("ProfileImage", "User")');

public ActionResult ProfileImage()
{开发者_运维百科
            return PartialView("_ProfileImage");
}

What I'd like to do is pass the model from the "parent" view to the controller which can then bind it to the partial when it is returned:

("#tab0").load('@Url.Action("ProfileImage", "User", new {model=model})');

public ActionResult ProfileImage(UserViewModel model)
{
            return PartialView("_ProfileImage", model);
}

Is this possible? how is this normally done? Where you have the model data in one view and you'd like to pass it to a asynchronously loaded partial view?


You could create a ToJson method on your viewmodel, which could be something like this:

        public IHtmlString ToJson()
        {
            return MvcHtmlString.Create(Json.Encode(this));
        }

It just serializes the viewmodel into a json. The IHtmlString returntype makes sure the output isn't encoded in your view. The call to your controller would be something like this:

("#tab0").load('@Url.Action("ProfileImage", "User", new {model=model.ToJson()})');

The json modelbinder can recreate the viewmodel on the serverside. You probably run into some problems along the way, but nothing unsolvable I guess.

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