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Problem with not() selector in IE8

开发者 https://www.devze.com 2023-03-30 09:10 出处:网络
I\'m having problems with the following line of jQuery code var controls = selectedForm.find(\'input:not(type=\"hidden\"), checkbox, select, textarea\');

I'm having problems with the following line of jQuery code

 var controls = selectedForm.find('input:not(type="hidden"), checkbox, select, textarea');

What I'm trying to do is to select al开发者_StackOverflowl the elements in selectedForm that are not <input type='hidden'....>. selectedForm is a previous selector that selects the form object of interest. There a total of 5 fields inside this form, one of which is the hidden input field.

My problem is that in IE8, the variable "control" contains all 5 fields inside the form. In FF6, this works correctly and returns the 4 fields I'm interested in.

I'm assuming that I have a syntax error, but I cannot see what it is.


Note you are trying to use an attribute equals selector for the attribute "type" which should be enclosed with brackets:

var controls = selectedForm.find('input:not([type="hidden"]), checkbox, select, textarea');


John Hartsock correctly identified the problem there (must use [type="hidden"]), however you can also write that query without using the :not selector:

selectedForm.find('input[type!="hidden"], checkbox, etc');

http://api.jquery.com/attribute-not-equal-selector/

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