This line of code:
if ( new RegExp("\\b" + arrCategorySort[i]+ "\\b", 开发者_如何学Python"g").test(titleText) )
{
catFound = true;
}
works perfect in Firefox (6.0), and in IE (7.0), but not in Chrome (13.0.782.112)
do you have any idea why?
Put a try/catch around your code and display the value that is causing the exception :
try {
if ( new RegExp("\\b" + arrCategorySort[i]+ "\\b", "g").test(titleText) )
catFound = true;
}
catch (e) {
confirm (e + ' : at index ' + i + ', category is "' + arrCategorySort[i] + '"');
}
The problem is that your arrCategorySort[i]
as a string contains special characters as far as the RegExp parser is concerned (e.g. {}
and []
). With your string in place, you're trying to parse regexp
/\bfunction (a,b){var c=b||window,d=[];for(var e=0,f=this.length;e<f;++e){if(!a.call(c,this[e],e,this))continue;d.push(this[e])}return d}\b/
After your (a,b)
in the beginning, in {}
you have var ...
however {}
mean repeated pattern and expect to have a number between them (or two numbers). What you really need is to escape all special chars: {}[]|()\,.*+
- by prepending '\' character in front of each of them. (There may be a couple more, escapes me at the moment.)
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