here is the thing, I want to (probably not the best thing to do) have the ability to call some class constructor that receives as a parameter a pointer to the class who's calling (ufff!!!). Well in code looks better, here it goes, as I do it in C#.
public class SomeClass
{
SomeOtherClass someOtherClass;
//Constructor
public SomeClass(SomeOtherClass someOtherClass)
{
this->someOtherClass = someOtherClass;
}
}
public class SomeOtherClass
{
public SomeOtherMethod()
{
开发者_开发知识库 SomeClass c = new SomeClass(this);
}
}
So, How can I achieve the same result in c++? Thanx in advance.
class SomeOtherClass; // forward declaration (needed when used class is not visible)
class SomeClass
{
SomeOtherClass *someOtherClass;
public:
SomeClass(SomeOtherClass *some) : someOtherClass(some)
{} // this is called initialization at constructor (not assignment)
}
class SomeOtherClass
{
public:
SomeOtherMethod()
{
SomeClass *c = new SomeClass(this);
}
}
Having answered your requirements above, also note that in C++ you really don't need to declare objects always with new
. If you declare,
SomeOtherClass someOtherClass;
then it means that you have an object of SomeOtherClass
named someOtherClass
.
probably not the best thing to do
It might not be a bad idea. However, every time you use pointers in C++, you must be completely clear about how it will be used: what kind of thing is being pointed to (not just the type of the pointer, but scalar vs. array, etc.), how the pointed-at thing gets there (e.g. via new
? As part of some other object? Something else?), and how it will all get cleaned up.
How can I achieve the same result in c++?
Almost identically, except of course that C++ does not use new
when you create a local instance by value (so we instead write SomeClass c = SomeClass(this);
, or more simply SomeClass c(this);
), and we must be aware of the pointer vs. value types (so SomeClass::someOtherClass is now a SomeOtherClass *
, which is also the type we accept in the constructor). You should also strongly consider using initialization lists to initialize data members, thus SomeClass::SomeClass(SomeOtherClass* someOtherClass): someOtherClass(someOtherClass) {}
.
You can do pretty much the same thing in C++ as well:
class B;
class A
{
public:
A (B * b) : pb (b) { }
private:
B * pb;
};
class B
{
public:
B () : a (this) { }
private:
A a;
};
The question is, do you really need that?
Maybe like this :)
class SomeOtherClass;
class SomeClass
{
private:
SomeOtherClass * someOtherClass;
public:
SomeClass(SomeOtherClass *someOtherClass)
{
someOtherClass = someOtherClass;
}
};
class SomeOtherClass
{
public:
void SomeOtherMethod()
{
SomeClass *c = new SomeClass(this);
}
};
'this' is a pointer-to-const in member functions (methods) declared as const. So:
void f1(X* p);
void f2(const X* p);
class X {
void m1() {
f1(this); // OK
f2(this); // also OK
}
void m2() const {
f2(this); // OK
f1(this); // error, 'this' is a pointer to const X
}
};
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