How to stop the execution of .sh script at certain time?

I have the following script which ensure that a .php file will be invoked every 3 seconds.

#!/bin/bash

for (( i=0; i<43200; i++ ))
do

/usr/bin/php /var/www/vhosts/mydoma开发者_StackOverflowin.com/httpdocs/somefile.php


sleep 3
done

I would like to be able to stop the script excecution if the time is 23:58:59

Anyone can help me?

Thanks, Zoran

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case `date +%H%M` in 2359) break ;; esac

Edit: I discovered the zero padding in the date formatting string was not portable, so I took it out. It's not useful or necessary in this case anyway.

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AGAIN me.

since your script has no imput youmcan try to launch yor script in the following way:

./yourscript.sh & sleep 10 && kill %1 && fg

give it a try.

Se

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I think there is no direct way without using a scripting language like python or perl.

here if yo want there is te perl script already implemented:

http://www.cyberciti.biz/faq/shell-scripting-run-command-under-alarmclock/

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Utilization summary:

Create a file installTimeout.sh containing the following:

wget http://pilcrow.madison.wi.us/sw/doalarm-0.1.7.tgz
tar -zxvf doalarm-0.1.7.tg
cd doalarm-0.1.7
make

and run the command:

source installTimeout.sh

now it's transparent to you. When you want to give a timeout to your script yo just have to run:

doalarm 20 your script

Best, Ste