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Jquery methods?

开发者 https://www.devze.com 2023-03-29 17:40 出处:网络
I keep seeing codes like this: $(document.documentElement).keyup( function(event) { var slides = $(\'#slides .pagination li\'),

I keep seeing codes like this:

  $(document.documentElement).keyup( function(event) {
    var slides = $('#slides .pagination li'),
        current = slides.filter('.current');

    switch( event.keyCode ) {
      case 37: // Left arrow
        if ( slides.filter(':first').is( current ) ) {
          slides.filter(':last').find('a').click();
       开发者_开发技巧 } else {
          slides.eq( slides.index(current) - 1 ).find('a').click();
        }
        break;
      case 39: // Right arrow
        if ( slides.filter(':last').is( current ) ) {
          slides.filter(':first').find('a').click();
        } else {
          current.find('+ li').filter(':first').find('a').click();
        }
        break;
    }
  });

For a line like this: current = slides.filter('.current');, .filter() is a jquery method, right? Then shouldn't it be current = $(slides).filter('.current');.

Does it work the way it is done in the code? Why?


slides is a jQuery object so you don't need to wrap it in $() like you do with a DOM object.

So slides.filter('.current') works like $('#slides .pagination li').filter('.current'). It's important to keep track of whether your objects are jQuery selectors, jQuery objects, and/or DOM objects.

Some people like to name their jQuery objects like var $slides as a mental note.


slides is already 'jQuery'ed: notice that it's defined using the $ sign. so there's no need to wrap it with a $ again.

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