I have the below code, which delivers between 1 and 3 results each time.
However, i wish to have the total value of the (up to) three results, rather than having them listed.
I can not simply wrap the whole coding in select sum ()
without getting the above error
Any help greatfully appreicated
--
select
case when sum(w.Value) > 3*sum(isnull (m.FFT1*m.FFL3V,0)
+ isnull (m.FFT2*m.FFL3HCV,0)
+ isnull (m.FFT3*m.FFFinanceSettleV,0)
+ isnull (m.FFT4*m.FFFinanceSettleHCV,0)
+ isnull (m.FFT5*m.FFL4V,0)
+ isnull (m.FFT6*m.FFL4HCV,0))
/count(w.ptmatter)
then CAST (SUM(w.Value) AS NUMERIC(38,2))
else (
select sum (isnull (m.FFT1*m.FFL3V,0)
+ isnull (m.FFT2*m.FFL3HCV,0)
+ isnull (m.FFT3*m.FFFinanceSettleV,0)
+ isnull (m.FFT4*m.FFFinanceSettleHCV,0)
+ isnull (m.FFT5*m.FFL4V,0)
+ isnull (m.FFT6*m.FFL4HCV,0))
/ count(w.ptmatter))
end
from dbo.workinprogress as w
full join dbo.matterdatadef as m
on (w.ptmatter = m.ptmatter)
where (w.time <> 0)
and (w.ptclient=
(select top 1 ptclient from workinprogress
where ptmatter=$matter$))
and (m.lsccert =
(select lsccert
from matterdatadef
where ptmatter=$matter$)
or (m.ptmatter=$matter$))
group by m.ptmatter
What about wrapping the whole thing in a subquery?
SELECT SUM(v) FROM (
select case when sum(w.Value) >
3*sum (
isnull (m.FFT1*m.FFL3V,0) +
isnull (m.FFT2*m.FFL3HCV,0) +
isnull (m.FFT3*m.FFFinanceSettleV,0) +
isnull (m.FFT4*m.FFFinanceSettleHCV,0) +
isnull (m.FFT5*m.FFL4V,0) +
isnull (m.FFT6*m.FFL4HCV,0)
)/count(w.ptmatter)
then CAST (SUM(w.Value) AS NUMERIC(38,2))
else (
select sum (
isnull (m.FFT1*m.FFL3V,0) +
isnull (m.FFT2*m.FFL3HCV,0) +
isnull (m.FFT3*m.FFFinanceSettleV,0) +
isnull (m.FFT4*m.FFFinanceSettleHCV,0) +
isnull (m.FFT5*m.FFL4V,0) +
isnull (m.FFT6*m.FFL4HCV,0)
) / count(w.ptmatter))
end AS v
from dbo.workinprogress as w
full join dbo.matterdatadef as m
on (w.ptmatter = m.ptmatter)
where (w.time <> 0)
and (w.ptclient = (select top 1 ptclient from workinprogress where ptmatter=$matter$))
and (m.lsccert = (select lsccert from matterdatadef where ptmatter=$matter$)
or (m.ptmatter=$matter$))
group by m.ptmatter
) as subQ
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