Jquery find all except

I have following HTML:

<div id="123" class="test">
   <div class="testMessage">Foo</div>
   <div><div class="testDate">2010</div></div>
   <div id="127" class="test">
      <div class="testMessage">Bar</div>
      <div><div class="testDate">2011</div></div>
   </div>
</div>

And I have following JS/jQuery code:

$(".test").find(".testDate").val("cool 2010");

How开发者_开发知识库 to change JS/jQuery to find "testDate" class element except in children "test" class block without using children?

P.S. I know only about class name and I don't know how many divs can be nested.

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Update

Its probably the weirdest selector I've ever written:

$("div.test").not(':has(> .test)').siblings().find('.testDate').text('cool 2010');

Demo: http://jsfiddle.net/mrchief/6cbdu/3/

Explanation:

$("div.test")             // finds both the test divs
  .not(':has(> .test)')   // finds the inner test div
  .siblings()             // get all other divs except the inner test div

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Try this and also div elements do not have a value property, use html() method to set the inner html or text()

$("div.test :not(.test)").find(".testDate").html("cool 2010");

If you can modify your main div id to "_123", you can straight away use the id selector like this

$("#_123 > div.testDate").html("cool 2010");

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I think the not() selector might help. You can learn more about it here: http://jsperf.com/jquery-css3-not-vs-not

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Anytime you try to select $('.test'), it will grab all elements with a class='test'. You need to start at the outermost body tag:

$('body').children('.test').children(':not(.test)').find('.testDate').text('cool 2010');