template name in twig main layout

Is it possible in twig to get the name of the child template in the layout? For Ex开发者_如何学Pythonample when calling:

$app['twig']->render('index.twig');

then in layout.twig, which is the main layout, it should ask:

if page is index.twig => include this javascript

I could do this with additional variables in the render call, but this seems to be bloated since the template name would indicate it already.

---

You are looking at this the wrong way. Imagine if you had a lot of views, then you'd have to do that for each one:

{% if _self.getTemplateName() == 'index.twig' %}
    <script src="{{ asset('somescript1') }}"></script>
{% endif %}
{% if _self.getTemplateName() == 'members.twig' %}
    <script src="{{ asset('somescript2') }}"></script>
{% endif %}
{% if _self.getTemplateName() == 'news.twig' %}
    <script src="{{ asset('somescript3') }}"></script>
{% endif %}
...

I find this approach pretty bad. What you can do, in your main layout file (lets assume its 'layout.html.twig' for this example) is make a block:

{% block javascripts %}
{% endblock %}

Then, in your view files:

{% extends 'AcmeHelloBundle::layout.html.twig' %}

....
{% block javascripts %}
<script src="asset('index.js')"></script>
{% endblock %}

Basically, you're overriding the block inside your layout file with new contents. In case you had anything inside your 'layout.html.twig' (like for example jquery), you'd also have to call parent():

{% extends 'AcmeHelloBundle::layout.html.twig' %}

....
{% block javascripts %}
{{ parent() }}
<script src="asset('index.js')"></script>
{% endblock %}

parent() just makes sure to copy all of the contents from the parent block too.