I have regular expression
(IX|IV|V?I{0,3}|M{1,4}|CM|CD|D?C{1,3}|XC|XL|L?X{1,3})
I use it to detect if there is any roman number in text.
eregi("( IX|IV|V?I{0,3}[\.]| M{1,4}[\.]| CM|CD|D?C{1,3}[\.]| XC|XL|L?X{1,3}[\.])", $title, $regs)
But format of roman number is always like this: " IV."... I have added in eregi example white space before number an开发者_Python百科d "." after number but I still get the same result. If text is something like "somethinvianyyhing" the result will be vi (between both)...
What am I doing wrong?
You have no space before VI
the space belongs always to the alternative before it was written and not to all. The same for the \.
it belongs always to the alternative where it was written.
Try this
" (IX|IV|V?I{0,3}|M{1,4}|CM|CD|D?C{1,3}|XC|XL|L?X{1,3})\."
See it here on Regexr
This will match
I.
II.
III.
IV.
V.
VI.
VII.
VIII.
IX.
X.
But not
XI.
MMI.
MMXI.
somethinvianyyhing
Your approach to match roman numbers is far from being correct, an approach to match the roman numbers more correct is this, for numbers till 50 (L)
^(?:XL|L|L?(?:IX|X{1,3}|X{0,3}(?:IX|IV|V|V?I{1,3})))$
See it here on Regexr
I tested this only on the surface, but you see this will really get complex and in this expression C, D and M are still missing.
Not to speak about special cases for example 4 = IV = IIII and there are more of them.
Wikipedia about Roman numbers
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