I want to 开发者_运维百科replace all occurent of "-", ":" characters and spaces from a string that appears in this format:
"YYYY-MM-DD HH:MM:SS"
something like:
var date = this.value.replace(/:-/g, "");
You were close: "YYYY-MM-DD HH:MM:SS".replace(/:|-/g, "")
/:-/g
means ":" followed by "-"
. If you put the characters in []
it means ":" or "-"
.
var date = this.value.replace(/[:-]/g, "");
If you want to remove spaces, add \s
to the regex.
var date = this.value.replace(/[\s:-]/g, "");
The regex you want is probably:
/[\s:-]/g
Example of usage:
"YYY-MM-DD HH:MM:SS".replace(/[\s:-]/g, '');
[]
blocks match any of the contained characters.
Within it I added the \s
pattern that matches space characters such as a space and a tab
\t
(not sure if you want tabs and newlines, so i went with tabs and skipped newlines).
It seems you already guessed that you want the g
lobal match which allows the regex to keep replacing matches it finds.
You can use either a character class or an |
(or):
var date = "YYYY-MM-DD HH:MM:SS".replace(/[:-\s]/g, '');
var date = "YYYY-MM-DD HH:MM:SS".replace(/:|-|\s/g, '');
精彩评论