Link in AlertDialog leaks window?

I've created a linkable text in an alert dialog, and make the TextView clickable, like this:

final SpannableString noRecords = new SpannableString("Sorry, no records could be found, please try again, or contact us at 867-5309");
Linkify.addLinks(noRecords);

AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle("No Records Found")
    .setMessage(noRecords)
    .setCancelable(true)
    .setPositiveButton("Ok", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int id) {
            dialog.cancel();
        }
    });

AlertDialog alert = builder.create();
alert.show();

((TextView)alert.findViewById(android.R.id.message)).setMovementMethod(LinkMovementMethod.getInstance());

This works, however when it's clicked it produces an error in logcat:

08-19 19:40:55.753: ERROR/WindowManager(5886): Activity com.blah.MainActivity has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@405d7010 that was originally added here 08-19 19:40:55.753: ERROR/WindowManager(5886): android.view.WindowLeaked: Activity com.blah.MainActivity has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@405d7010 that was originally added here

I think this is because the alert is not dismisse开发者_StackOverflow社区d before the link is clicked. Is there any way around this? I'd prefer not to be throwing any errors.

---

If you want to dispose the dialog before the activity is destroyed, you can override the onDestroy() event

@Override
public void onDestroy(){
    //Your dialog disposal code here

    super.onDestroy(); //Make sure you include this at the end.
}

Hope that helps