Executing code after a process is done - jQuery

I want to run:

$(".left").load("created.php");

after:

$("#placeholder").load("creat开发者_JAVA百科e.php")

I tried the following, but it didn't work:

$("#create").live("click", function() {
 if($("#placeholder").load("create.php")) {
  $(".left").load("created.php");
 }
})

---

The jQuery load() function runs asychronously. You need to use a callback function to run code after the first load completes.

The following code should suffice:

 $("#create").live("click", function() {
   $("#placeholder").load("create.php", function() {
     $(".left").load("created.php");
   });
 });

Enjoy!

---

call the created.php in the call back of first load

$("#placeholder").load("create.php",null,function(){

$(".left").load("created.php");

});

jquery load

---

Execute it in the success handler of the previous load

$("#placeholder").load("create.php", function(){
   $(".left").load("created.php");
});

---

if($("#placeholder").load("create.php")) 

this line means load create.php then return a jqxhr object which is not what you mean. use callback of load method: $("#placeholder").load("create.php", function(data){...}) Or use $.when and .then instead