I need a little help selecting the right triples from my st开发者_JS百科ore....
<a> a <type/1> .
<b> a <type/1> .
<c> a <type/1> .
<c> a <type/2> .
i want to select only elements which are type/1 and not type/2
What is the best way to achieve this using a sparql select query?
am looking for omething like:
select ?a where
{
?a a <type/1> .
!{ ?a a <type/2> }
}
Thanks,
:)
An alternative SPARQL 1.1 solution is to use MINUS
e.g.
SELECT ?a
WHERE
{
?a a <type/1> .
MINUS { ?a a <type/2> . }
}
MINUS
subtracts solutions that match its triple pattern from the existing matches.
In most cases using FILTER NOT EXISTS { }
and MINUS { }
are equivalent but beware there are some corner cases where this is not true - see the SPARQL 1.1 specification for some examples of this.
In SPARQL 1.0 that's a bit tricky:
SELECT ?a WHERE {
?a a <type/1>.
OPTIONAL {
?a a ?othertype .
FILTER (?othertype = <type/2>)
}
FILTER (!BOUND(?othertype))
}
The OPTIONAL
clause binds ?othertype
for any ?a
that has <type/2>
, and leaves it unbound for any ?a
that doesn't have it.
The final FILTER
then selects only those rows where ?a
was left unbound.
In SPARQL 1.1 it's much easier:
SELECT ?a WHERE {
?a a <type/1>.
FILTER NOT EXISTS { ?a a <type/2> . }
}
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