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Format timeval into "best units"

开发者 https://www.devze.com 2023-03-28 19:58 出处:网络
I am trying to write a benchmark program that takes about 20 minutes to complete because the actual functions need to be called at least 50 times.

I am trying to write a benchmark program that takes about 20 minutes to complete because the actual functions need to be called at least 50 times.

I used the following code:

struct timeval start, end;
long mtime, seconds, useconds;
gettimeofday(&start, NULL);
usleep(2000);
gettimeofday(&end,NULL);
seconds =end.tv_sec - start.tv_sec;
useconds=end.tv_usec - start.tv_usec; 
(mtime>1000)?cout<<"elapsed time in seconds:"<<setprecision(8)<<mtime/1000<<"seconds\n":cout<<"elapsed time in milliseconds: "<<setprecision(3)<<mtime<<" milliseconds\n"; 

but I am required to write it in such a way t开发者_如何学Pythonhat the output deduces the best units to use for the elapsed time and displays the results in those units. any suggestions how I can revise the above code for the requirement? thx!


My guess is that your "best unit" requirement is basically "human usable units." If so, take the time and

  • millisecs mod 1000 gives number of milliseconds
  • millisecs div 1000 gives seconds (where div is integer division)
  • seconds mod 60 gives number of seconds
  • seconds div 60 gives minutes

and so on.

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