------ main.c---------
#include <stdio.h>
#include <stdlib.h>
#include <dlfcn.h>
#include <string.h>
int main()
{
char* lib_name = "./a.out";
int array[5] = {1,2,3,4,5};
int size_a = sizeof(array)/sizeof(开发者_JS百科int);
void* handle = dlopen(lib_name, RTLD_NOW);
if (handle) {
printf("[%s] dlopen(\"%s\", RTLD_NOW): incarcare finalizata\n",
__FILE__, lib_name);
}
else {
printf("[%s] nu poate fi deschis: %s\n", __FILE__, dlerror());
exit(EXIT_FAILURE);
}
void (*subrutine_fortran)(int*, int*) = dlsym(handle, "putere");
if (subrutine_fortran) {
printf("[%s] dlsym(handle, \"_set_name\"): simbol gasit\n", __FILE__);
}
else {
printf("[%s] simbol negasit: %s\n", __FILE__, dlerror());
exit(EXIT_FAILURE);
}
subrutine_fortran(&array,&size_a);
//dlclose(handle);
for(int i=1;i<4;i++) {
array[i]=array[i]+1;
}
}
------ hello.f90 --------
subroutine putere(a,h) bind(c)
use ISO_C_BINDING
implicit none
integer(c_int) :: h
integer(c_int), dimension(h) :: a
integer i
do concurrent (i=0:5)
a(i)=a(i)*10
end do
!write (*,*) a
end subroutine
When I do a loop through array elements:
for(int i=1;i<4;i++) {
array[i]=array[i]+1;
}
I get a segmentation fault.
It doesn't happen when I write:
array[3]=array[3]+1
Your C-code is this:
int array[5] = {1,2,3,4,5};
int size_a = sizeof(array)/sizeof(int);
subrutine_fortran(&array,&size_a);
and your Fortran code is this:
subroutine putere(a,h) bind(c)
use ISO_C_BINDING
implicit none
integer(c_int) :: h
integer(c_int), dimension(h) :: a
integer i
do concurrent (i=0:5)
a(i)=a(i)*10
end do
!write (*,*) a
end subroutine
This is wrong a couple of ways - as Zack points out, Fortran arrays are 1-indexed (even when they come from somewhere else, like C). So this should start at 1. Also, if 0 was right, the size would be wrong. You want something like
do concurrent (i=1:h)
With that change, it works for me.
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