i have a directory listing like
seascaperecovered0088crop.jpg
seascaperecovered0096crop.jpg
seascaperecovered0098crop.jpg
seascaperecovered0101crop.jpg
seascaperecovered0103crop.jpg
seascap开发者_如何学Cerecovered0105crop.jpg
seascaperecovered0107crop.jpg
seascaperecovered0112crop.jpg
seascaperecovered0119crop.jpg
seascaperecovered0122crop.jpg
and i want to rename all files as seen here:
seascape_0122.jpg
i have tried something like this:
for f in `ls | egrep 'seascaperecovered.*\.jpg'`;
do mv $f ${f/seascaperecovered/seascape};
done
i have read that you can do this with mv, rename, sed, awk, etc. can someone point me to the easiest (and clearest, hopefully) way of accomplishing this in UNIX? FWIW, I am ssh'd into a Linux machine and running a bash shell.
thanks, jml
Very straightforward:
for i in seascaperecovered*.jpg; do A=${i/crop/}; mv $i ${A/recovered/_}; done
(Put echo
before the mv
first for a dry run.)
With bash regular expressions
for file in *; do
[[ "$file" =~ [0-9]+ ]] && mv "$file" seascape_${BASH_REMATCH[0]}.jpg
done
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