#include <iostream>
#include <vector>
#include <numeric>
using namespace std;
std::vector<float> num;
float mean (float num[], float n)
{
int i;
float sum=0;
for(i=0;i<n;i++)
sum=sum+num[i];
return (sum/n);
}
int main()
{
int minusElements;
int n;
cout << "Enter number of Elements:";
cin >> n;
minusElements = n - 1 ;
int i,j;
float temp;
float f;
for(i=0;i<n;i++)
{
cin >> f;
num.push_back(f);
}
cout << "Enter " << n << " numbers:\n";
for(i=0;i<n;i++)
cin >> num[i];
cin.get();
float m = mean(&num[0], num.size());
//if num is float[n] or float* (num of 开发者_高级运维elements = n)
float mean = std::accumulate(num, num + n, 0) / n;
cout<<mean;
}
//46 no match for 'operator+' in 'num + n'
push_back
is generally called on a vector
, not an array like int[]
.
You are using a regular C-style array instead of a std::vector
and the compiler is complaining.
num
should be declared as
std::vector<int> num;
It's pretty clear from the error message: num
is not an instance of a class so you can't call methods on it. Why do you think you can call push_back
on it? Where do you think push_back
is defined?
num
is not an std::vector
, so you can't call the push_back
method for it.
Maybe you intended to define num
like this :
std::vector<int> num;
Note that you'd have to modify the rest of the code accordingly of course.
int i,j, num[n];
-->
int i,j;
std::vector<int> num;
Since when asking questions could be replaced by code? Say something buddy.
Decide how you want to store your numbers, in either a vector or an array, and then use the operations that are available accordingly.
It seems that you edited heavily the question, as in the opening title the compiler is complaining when you try to perform an operation of a vector in num
as num
in that version is an array. Then the current code has the opposite problem: num
is defined as a vector and you are trying to apply an operation that is not available in vectors but rather to pointers.
The second error can be fixed by changing the call to std::accumulate
to use iterators:
float mean = std::accumulate(num.begin(), num.end(), 0) / n;
NOTE: It is a really bad idea to edit the question so that existing answers no longer make sense. You are new to StackOverflow, but expect your questions to be closed if you continue with this pattern.
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