Regular expression: which pattern would return true if both exact words were found?

If my regex pattern @"\b(word1|word2)\b" returns true when only 1 of the exact words is found, which pattern would return true if both exact words were found?

The only examples I found were like I did it and return true whenever 1 word was found but I want it to return true when all words were found. So multiples of the same word don't count. I need to know if at least 1 occurrence of all words exists.

Edit:

Example: "The q开发者_StackOverflow社区uick brown fox jumps over the lazy dog"

pattern: @"\b(fox|dog)\b" <---- returns true

pattern: @"\b(fox|elephant)\b" <---- returns true, I want it to return false.

Add: I have to be flexible since the amount of words to search for depends on my users.

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You can achieve this using lookaheads

(?=.*\bWord1\b)(?=.*\bWord2\b).*

See it here on Regexr

(?=.*\bWord1\b) is a positive lookahead. It checks if the pattern inside occurs within the string. It does not match anything!

To match the string there is the .* at the end, but this will only be matched, if both lookaheads are true, i.e. both of your words are found within the string.

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the simple answer is to have two regex expressions one for the first word, and one for the other, if both return true (and them), then the result is true.

@"\b(word1)\b" and @"\b(word2)\b"

You can check here also

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If you must,

@"\b(word1\b(.*\b)?word2|word2\b(.*\b)?word1)\b"

but it would be better to use two regular expressions.

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Stema's answer is the best imo.

The following is a simplified version of Charles

Given: "word and word2 and word3 and word4. word4 is a good guy, isn't he word1?"

(\bword4\b.\bword2\b|\bword2\b.\bword4\b)

BUT like i said Stema ftw