Hello friends,
I have a string like "/Date(1312628727617+0000)/" and this regular expression convert into Date format 开发者_开发知识库in iPhone so please provide any link or any idea to develop this functionality.
Thanks in advance.
Use the below method and pass your regular expression date /Date(1312628727617+0000)/ as parameter.
- (NSDate*) getDateFromJSON:(NSString *)dateString
{
// Expect date in this format "/Date(1268123281843)/"
int startPos = [dateString rangeOfString:@"("].location+1;
int endPos = [dateString rangeOfString:@")"].location;
NSRange range = NSMakeRange(startPos,endPos-startPos);
unsigned long long milliseconds = [[dateString substringWithRange:range] longLongValue];
NSLog(@"%llu",milliseconds);
NSTimeInterval interval = milliseconds/1000;
return [NSDate dateWithTimeIntervalSince1970:interval];
}
EDIT:
NSDateFormatter *dateForm = [[NSDateFormatter alloc] init];
[dateForm setDateFormat:@"yyyy-MM-dd hh:mm:ss"];
NSString *dateStr = [dateForm stringFromDate:<YourNSDateObject>];
[dateForm setDateFormat:@"<Your Desired Date Format>"];
NSDate *desireddate = [dateForm dateFromString:dateStr];
Hope this helps you.
See this: - (NSDate *)dateFromString:(NSString *)string @ below link
http://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSDate_Class/Reference/Reference.html#//apple_ref/doc/c_ref/NSDate
Have a look at dateFromString:
at http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSDateFormatter_Class/Reference/Reference.html. You will find the many formats supported.
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