Show Hide div if, if statement is true_问答_开发者

开发者 https://www.devze.com 2023-03-26 23:44 出处：网络

My code works to a point. What I want is that when this if statemen开发者_运维百科t is false, the <div> doesn\'t show

My code works to a point. What I want is that when this if statemen开发者_运维百科t is false, the <div> doesn't show

<?php
    $query3 = mysql_query($query3);
    $numrows = mysql_num_rows($query3);
    if ($numrows > 0) {
        $fvisit = mysql_fetch_array($result3);
    }
    else {
    }
?>

You can use css or js for hiding a div. In else statement you can write it as:

else{
?>
<style type="text/css">#divId{
display:none;
}</style>
<?php
}

Or in jQuery

else{
?>
<script type="text/javascript">$('#divId').hide()</script>
<?php
}

Or in javascript

else{
?>
<script type="text/javascript">document.getElementById('divId').style.display = 'none';</script>
<?php
}

This does not need jquery, you could set a variable inside the if and use it in html or pass it thru your template system if any

<?php
$showDivFlag=false
$query3 = mysql_query($query3);
$numrows = mysql_num_rows($query3);
if ($numrows > 0){
    $fvisit = mysql_fetch_array($result3);
    $showDivFlag=true;
 }else {

 }

?>

later in html

  <div id="results" <?php if ($showDivFlag===false){?>style="display:none"<?php } ?>>

A fresh look at this(possibly)
in your php:

else{
      $hidemydiv = "hide";
}

And then later in your html code:

<div class='<?php echo $hidemydiv ?>' > maybe show or hide this</div>

in this way your php remains quite clean

Use show/hide method as below

$("div").show();//To Show

$("div").hide();//To Hide

<?php
$divStyle=''; // show div

// add condition
if($variable == '1'){
  $divStyle='style="display:none;"'; //hide div
}

print'<div '.$divStyle.'>Div to hide</div>';
?>

Probably the easiest to hide a div and show a div in PHP based on a variables and the operator.

<?php 
$query3 = mysql_query($query3);
$numrows = mysql_num_rows($query3);
?>
<html>
<?php if($numrows > null){ ?>
     no meow :-(
<?php } ?>

<?php if($numrows < null){ ?>
     lots of meow
<?php } ?>
</html>

Here is my original code before adding your requirements:

<?php 
$address = 'meow';
?>
<?php if($address == null){ ?>
     no meow :-(
<?php } ?>

<?php if($address != null){ ?>
     lots of meow
<?php } ?>

from php you can invoke jquery like this but my 2nd method is much cleaner and better for php

if($switchView) :?>
 <script>$('.container').hide();</script>
 <script>$('.confirm').show();</script>
<?php endif;

another way is to initiate your class and dynamically invoke the condition like this

$registerForm ='block';

then in your html use this

<div class="col" style="display: <?= $registerForm?>">

now you can play with the view with if and else easily without having a messed code example

if($condition)  registerForm = 'none';

Make sure you use 'block' to show and 'none' to hide. This is far the easiest way with php

If you wrap the whole block within the <?php ?> tags in the initial 'if' statement and don't specify an 'else', this condition is not satisfied, returns false so therefore won't display the <div>