I am trying to show the form only if submit is not set, and if set then upload file and show link to the same page so that a new file could be uploaded again.
It shows the form even after I click on the submit button. I have not added an upload script now.
<body>
<?php
if (isset($_POST['submit']))
{
$output_form == 'no';
echo 'hiiiii';
}
else {
$output_form = 'yes';
}
if($output_form = 'yes')
{
?>
<form enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input type="file" name="uploadpic" />
<input type="submit" value="Upload" n开发者_JS百科ame="submit" />
</form>
<?php
}
?>
</body>
$output_form == 'no';should be$output_form = 'no';if ($output_form = 'yes')should beif ($output_form == 'yes')
= is assignment, whereas == is a comparison.
Also, your form will use GET because you did not ask it to use POST with method="POST".
You're missing your method on the form element.
<form enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
You can also use print_r($_POST) to see what's in the array.
Here's an example of it working, as well as the code.
http://www.wecodesign.com/demos/stackoverflow-7018639.php
if($output_form = 'yes')
should be
if($output_form == 'yes')
The way you have it now, you're assigning a value.
It should be
if($output_form == 'yes')
You doing assignment, use comparison:
if($output_form == 'yes')
Ensure that you're actually SETTING the no value as well:
$output_form == 'no';
Should be
$output_form = 'no';
![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif)
加载中,请稍侯......
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