XSLT - Dealing with multiple child-nodes

I've got to write and XSLT to deal with the following XML:

<Attachments>
    <string>http://lurl/site/Lists/Note/Attachments/image1.jpg</string>
    <string>http://lurl/site/Lists/Note/Attachments/image3.jpg</string>
</Attachments>

I need to output the 2 strings, although for some records there are more then 2 strings to output.

e.g.

<ul>
  <li>http://lurl/site/Lists/Note/Attachments/image1.jpg</li>
  <li>http://lurl/site/Lists/Note/Attachments/image3.jpg</li>
</ul>

开发者_如何转开发Do i need a for each or a while?

---

A simple apply-templates should do it.

<xsl:template match="Attachments">
  <ul>
    <xsl:apply-templates/>
  </ul>
</xsl:template>

<xsl:template match="string">
  <li><xsl:value-of select="."/></li>
</xsl:template>

---

You don't need any kind of iteration. Use the Identity transformation and override:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:output indent="yes"/>

    <xsl:template match="node()|@*">
        <xsl:copy>
            <xsl:apply-templates select="node()|@*"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="Attachments">
        <ul>
            <xsl:apply-templates select="node()|@*"/>
        </ul>
    </xsl:template>

    <xsl:template match="string">
        <li><xsl:value-of select="."/></li>
    </xsl:template>

</xsl:stylesheet>

---

One approach would be to use an xsl:template

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:template match="/">
  <ul>
    <xsl:apply-templates />
  </ul>
</xsl:template>

<xsl:template match="/Attachments/string">
  <li>
    <xsl:value-of select="." />
  </li>
</xsl:template>
</xsl:stylesheet>

---

<ul>
<xsl:for-each select="//Attachments/string">
  <li>
    <xsl:value-of select="text()" />
  </li>
</xsl:for-each>
</ul>