Replacing parameter values in URLs

// Below are a number of strings which need ammending
$string = "www.development_test.php?action=show_development_crs&test1&test2";
$string = "www.development_test.php?action=show_rfw&test1";
$string = "www.development_test.php?action=show_development_crs";

I need to write a preg_replace() function which replace the value between "=" + "&" or in the case of the bottom string everything after "=" when & doesnt exi开发者_如何转开发st with "newAction"..

Does anyone have any ideas?

This is what I have tried so far, but failed:

public function test1()
{
    $action      = "newAction";
    $string      = "www.development_crs.php?action=show_development_crs&test1&test2";
    $pattern     = '/(action=)(.*)(&)/';
    $replacement = "action=$action&";

    $string = preg_replace($pattern, $replacement, $string);

    echo $string;
}

---

$action      = 'newAction';
$string      = 'www.development_crs.php?action=show_development_crs&test1&test2';
$pattern     = '/action=[^&]+(.*)/';
$replacement = "action=$action$1";

$string = preg_replace($pattern, $replacement, $string);
echo $string;

Output:

www.development_crs.php?action=newAction&test1&test2

---

try the pattern below

$pattern='/action=([a-z0-9_\-%]+)&/';

---

$pattern     = '/action=.*?(&|$)/';
$replacement = "action=$action$1";

---

I can see a few problems with your pattern. Not that I'm a regex expert however,

Try something like this:

/action=[^&]+/

or

/action=[^&]*/

This will match 'action=' and then the rest of the string until it encounters a &. The + means that it must have at least one character between the = and the & to accept the string.

Hope this helps :)