Here is my batch script file. There are 2 scenarios
- Scenario 1
@echo off
set name=
set /P TypeName=Name: %=%
if %TypeName% == "abcd" goto correctName
else goto wrongName
:correctName
echo Correct Name
:end
:wrongName
echo Wrong Name
:end
When i type abcd as the input, i get 'else' is not recognized as an internal or external command,operable program or batch file
Wrong Name
- Scenario 2
@echo off
set n开发者_开发问答ame=
set /P TypeName=Name: %=%
if %TypeName% EQA "abcd" goto correctName
if %TypeName% NEQ "abcd" goto wrongName
:correctName
echo Correct Name
:end
:wrongName
echo Wrong Name
:end
When i type abcd as the input, i get EQA was unexpected at this time.
Is there something wrong in my script?Am I missing something here
ELSE
should be on the same line with theIF
keyword or on the same line with the closing bracket that pertains to theIF
.Like this:
IF %TypeName% == "abcd" GOTO correctName ELSE GOTO wrongName
Or like this:
IF %TypeName% == "abcd" ( ECHO Correct. GOTO correctName ) ELSE GOTO wrongName
The correct keyword for the Equal operator is
EQU
:IF %TypeName% EQU "abcd" GOTO correctName
The first example is almost right, except that the format of an IF/ELSE statement in a batch file is as follow:
IF <statement> (
..
..
) ELSE (
...
...
)
So just you use that format and it should work.
You shouldn't necessarily need to use the else, like this
@echo off
set name=
set /P TypeName=Name: %=%
if %TypeName% == "abcd" goto correctName
goto wrongName
:correctName
echo Correct Name
:end
:wrongName
echo Wrong Name
:end
If the %TypeName% == "abcd" it will jump to :correctName, if it doesn't it will simply fall to the next line and jump to :wrongName.
To give an end to this post,i got the expected output this way-
@echo off
set name=
set /P TypeName=Name: %=%
if "%TypeName%" == "abcd" (
echo Correct Name
) else (
echo Wrong Name
)
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