Yesterday I made a small script with some help to read .csv files. I though I found a way to read the first value and store it, but for some reason it stores the last value instead.
I store what I thought should be the first value under value1, and re-display it to make sure it displays properly and is in fact being stored under a callable variable.
Does anyone know what is wrong with this code? I think I should be using vectors but as I read the reference sheets I find on the internet about them I am being a little thrown of. Any help is appreciated.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main ()
{
int loop = 1;
string value;
string value1;
while(loop = 1)
{
cout << "Welcome! \n" << endl;
ifstream myfile;
myfile.open ("C:/Documents and Settings/RHatfield/My Documents/C++/Product Catalog Creator/Source/External/Sample.csv");
while 开发者_运维百科(myfile.good())
getline ( myfile, value, ',' );
cout << string ( value) << endl;
value1 = value;
cout << value1;
myfile.close();
system("PAUSE");
return 0;
}
}
Your error seems to be in pure code formatting.
while (myfile.good())
There is no {}
after the loop. So only next line is repeated.
The following code is executed after reading of the whole file.
cout << string ( value) << endl;
Thus value
stores the last line of the file.
You may want to change the condition in your while
loop:
char separator;
int value1;
int value2;
int value3;
while (myfile >> value1)
{
// Skip the separator, e.g. comma (',')
myfile >> separator;
// Read in next value.
myfile >> value2;
// Skip the separator, e.g. comma (',')
myfile >> separator;
// Read in next value.
myfile >> value3;
// Ignore the newline, as it is still in the buffer.
myfile.ignore(10000, '\n');
// Process or store values.
}
The above code fragment is not robust but demonstrates the concept of reading from a file, skipping non-numeric separators and processing the end of the line. The code is optimized either.
精彩评论