I don't know how to do the following:
find all instances of '/\s[2-9]\)/'
and replace the space with a <br />
tag.
$preg_num = ' /\s[2-9]\)/';
$preg_fix = "'/<br>/[2-9]\)'";
preg_replace($preg_num,$preg_fix,$notes);
What do I need to change the $开发者_如何学Pythonpreg_fix variable to?
Using a lookahead is simpler than a backreference, IMHO.
$preg_num = '/\s(?=[2-9]\))/';
$preg_fix = '<br/>';
preg_replace($preg_num,$preg_fix,$notes);
This way, you are only replacing the space with the <br/>
.
The replacement string is not treated as a regex — it is more like a literal string. If you are trying to put whatever digit [2-9]
that was matched in the original regex into the replacement string, capture the character as a group and use a backreference.
$preg_num = '/\s([2-9])\)/';
$preg_fix = "<br />$1)'";
preg_replace($preg_num,$preg_fix,$notes);
For more information:
preg_replace
'sreplacement
parameter documentation- Regular expression grouping: "Use Round Brackets for Grouping"
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