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Parse error: syntax error

开发者 https://www.devze.com 2023-03-24 23:52 出处:网络
what is this error ? Parse error: syntax error, unexpected T_VAR in D:\\xampp\\htdocs\\mehdi\\application\\libraries\\phpass-0.1\\PasswordHash.php on line 32

what is this error ?

Parse error: syntax error, unexpected T_VAR in D:\xampp\htdocs\mehdi\application\libraries\phpass-0.1\PasswordHash.php on line 32

code:

$iteration_count_log2 = $params['phpass_hash_strength'];
        $portable_hashes = $params[开发者_开发问答'phpass_hash_portable']; 
    var $itoa64; //line 32
    var $iteration_count_log2;
    var $portable_hashes;
    var $random_state;


You must not use var to declare a variable : just assign a value to it, when you need it :

$your_variable = 5647;


And if you really want your variables listed beforehand, just assign something that would mean no-value to them, like, for instance, null :

$your_variable = null;


Just so you know : var was used, in PHP 4 (and, as such, is still valid in PHP 5, for that same usage) to declare classes properties.


Remove 'var' from each of your variables.

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