There are many ways functions can be defined in Scala, which 开发者_运维技巧leads to confusion about when exactly function parameter types are required. I usually start with the simplest possible definition and work my way down until compiler errors go away. I'd rather actually understand how this works.
For example:
_ + _
(x, y) => x + y
(x: Int, y: Int) => x + y
def sum(x: Int, y: Int) = x + y // as pointed out, this is a method,
// which not a function
Bonus points for a link to the documentation.
Well there are some corner cases like: a recursive method must be explicitly typed, but normally the rule of thumb is as follows: types have to come from somewhere.
Either they come from the reference part:
val function: (Int, Int) => Int = _ + _
or from the object part:
val function = (x: Int, y: Int) => x + y
does not really matter. (in Scala!)
I know you question is about functions, but here is a similar example to illustrate Scala's type inference:
// no inference
val x: HashMap[String, Int] = new HashMap[String, Int]()
val x: HashMap[String, Int] = new HashMap[String, Int]
// object inference
val x: HashMap[String, Int] = new HashMap()
val x: HashMap[String, Int] = new HashMap
val x: HashMap[String, Int] = HashMap() // factory invocation
// reference inference
val x = new HashMap[String, Int]()
val x = new HashMap[String, Int]
val x = HashMap[String, Int]() // factory invocation
// full inference
val x = HashMap("dog" -> 3)
EDIT As requested I add the higher-order function case.
def higherOrderFunction(firstClassFunction: (Int, Int) => Int) = ...
can be called like this:
higherOrderFunction(_ + _) // the type of the firstClassFunction is omitted
But, this is not a special case. The type of the reference is explicitly mentioned. The following code illustrates a similar example.
var function: (Int, Int) => Int = null
function = _ + _
This is roughly equivalent to the higher-order function case.
Your fourth example is a method, not a function (see this question). You must specify the types of arguments to a methods. The return type of a method can be inferred, unless the method is recursive, in which case it must be specified explicitly.
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