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How to send Https Post request in java

开发者 https://www.devze.com 2023-03-24 18:31 出处:网络
I want to login to application from java code. Here is my code... String httpsURL = \"https://www.abcd.com/auth/login/\";

I want to login to application from java code. Here is my code...

String httpsURL = "https://www.abcd.com/auth/login/";

String query = "email="+URLEncoder.encode("abc@xyz.com","UTF-8"); 
query += "&";
query += "password="+URLEncoder.encode("abcd","UTF-8") ;

URL myurl = new URL(httpsURL);
HttpsURLConnection con = (HttpsURLConnection)myurl.openConnection();
con.setRequestMethod("POST");

con.setRequestProperty("Content-length", String.valueOf(query.length())); 
con.setRequestProperty("Content-Type","application/x-www- form-urlencoded"); 
con.setRequestProperty("User-Agent", "Mozilla/4.0 (c开发者_运维技巧ompatible; MSIE 5.0;Windows98;DigExt)"); 
con.setDoOutput(true); 
con.setDoInput(true); 

DataOutputStream output = new DataOutputStream(con.getOutputStream());  


output.writeBytes(query);

output.close();

DataInputStream input = new DataInputStream( con.getInputStream() ); 



for( int c = input.read(); c != -1; c = input.read() ) 
System.out.print( (char)c ); 
input.close(); 

System.out.println("Resp Code:"+con .getResponseCode()); 
System.out.println("Resp Message:"+ con .getResponseMessage()); 

but i can not login, it returns back only login page.

If anybody can, please help me to understand what am i doing wrong.


Wrong :- (Extra space is there in mid of www- form)

con.setRequestProperty("Content-Type","application/x-www- form-urlencoded"); 

Correct

 con.setRequestProperty("Content-Type","application/x-www-form-urlencoded"); 


You could be getting a 400 for a few reasons, but usually becaue the data isn't formatted correctly (maybe it takes XML?). Perhaps a record already existed. Try it using postman to see what result you get.

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