Here is my problem, I am using a layout that has a sticky footer (using the cssstickyfooter.com method). inside my container div i have a content开发者_运维问答 div that has four other divs inside of it. like so:
<div class="container">
<div class="content">
<div id="1"></div>
<div id="2"></div>
<div id="3"></div>
<div id="4"></div>
</div>
</div>
<div class="footer"></div>
In order for the sticky footer to work correctly all of the divs need to have position:relative; set, because the divs will have content that will be different lengths and they need to re-size accordingly. however where my dilemma begins is that i need to have divs 1-4 have position:absolute; set, so that they will stack on top of each other having the same (x,y) position.
is there any way to achieve what i need?
I recommend Ryan Fait's sticky footer, works very well!
* {
margin: 0;
}
html,
body {
height: 100%;
}
.wrapper {
min-height: 100%;
height: auto !important;
/* This line and the next line are not necessary unless you need IE6 support */
height: 100%;
margin: 0 auto -20px;
/* the bottom margin is the negative value of the footer's height */
}
.footer,
.push {
height: 20px;
/* .push must be the same height as .footer */
}<body>
<div class="wrapper">
<p>Your website content here.</p>
<div class="push"></div>
</div>
<div class="footer">
<p>Copyright (c) 2008</p>
</div>
</body>I typically just use the following to "stick" a div to the bottom of the page (or container):
.footer {position:absolute;bottom:0;left:0;}
Once you set position to absolute, it becomes independent of external divs and their position/dimensions.
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