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How to insert ' in DB using Hibernate

开发者 https://www.devze.com 2022-12-15 16:57 出处:网络
I\'m using hibernate for all DB operations. My problem is that, I want to insert an string in table which contains \' e.g. rea9\'e开发者_开发技巧a/rea9\'ea.

I'm using hibernate for all DB operations.

My problem is that, I want to insert an string in table which contains ' e.g. rea9'e开发者_开发技巧a/rea9'ea. While inserting it I'm getting the following exception

Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ea/rea9','6a8b2622d3b8ab7de31c0e2496cef2bd',5840,'')' at line 1 at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:406) at com.mysql.jdbc.Util.getInstance(Util.java:381)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1030)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3515)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3447)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1951) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2101)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2554) at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1761)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2046)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1964)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1949)
    at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.executeUpdate(NewProxyPreparedStatement.java:105)
    at org.hibernate.engine.query.NativeSQLQueryPlan.performExecuteUpdate(NativeSQLQueryPlan.java:165)
    ... 8 more

How to solve the problem?


First, have you mapped your table to a POJO? This is, of course, the heart of what makes Hibernate so powerful. If you have, then inserting any String is easy:

MyPOJO m = new MyPOJO();
m.setName("asdf'!@#$%^&*()\"1234567890");
HibernateUtil.currentSession().save(m);

If you need to include any string in an HQL statement, then it should be a parameter:

HibernateUtil.currentSession().createQuery("from MyTable where Name=:name")
            .setParameter("name","asdf'!@#$%^&*()\"1234567890")
            .list();
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