开发者

Add up a points column based on an id from within the same mysql table

开发者 https://www.devze.com 2023-03-24 05:26 出处:网络
OK the database is layed out as (only columns being used are listed): Table Name: race_stats Columns: race_id, user_id, points, tournament_id

OK the database is layed out as (only columns being used are listed):

Table Name: race_stats
Columns: race_id, user_id, points, tournament_id

Table Name: user
Columns: user_id, driver

Table Name: race
Columns: race_id, race_name

Table Name: tournament
Columns: tournament_id, tournament_name

This is my current query:

$query = "

SELECT user.user_id, user.driver, race_stats.points, race_stats.user_id, 
   SUM(race_stats.points) AS total_points "." 
FROM user, race_stats, tournament, race "." 
WHERE race.race_id=race_stats.race_id 
   AND user.user_id=race_stats.user_id 
   AND tournament.tournament_id=race_stats.tournament_id 
GROUP BY driver 
ORDER BY total_points DESC 
LIMIT 0, 15

";

Ok the query works but it is adding them all up for all the available races from the race_stats.race_id column as the total points. I have racked my brain beyond recognition to fix this but I just can't quite seem to find the solution I need. I'm sure it has to be an easy fix but I just can't get it. Any help is greatly appreciate开发者_开发知识库d.

///////////////////EDITED WITH RAW VALUES//////////////////////

INSERT INTO `race_stats` (`id_race`, `race_id`, `user_id`, `f`, `s`, `race_interval`, `race_laps`, `led`, `points`, `total_points`, `race_status`, `tournament_id`, `driver`, `tournament_name`) VALUES

(1, 1, 4, 1, 4, '135.878', 60, '2', 180, 0, 'Running', 1, 'new_driver_5', ''),
(2, 1, 2, 2, 2, '-0.08', 60, '22', 175, 0, 'Running', 1, 'new_driver_38', ''),
(3, 1, 5, 3, 5, '-11.82', 60, '2', 170, 0, 'Running', 1, 'new_driver_94', ''),
(4, 2, 2, 1, 15, '138.691', 29, '6', 180, 0, 'Running', 2, 'new_driver_38', ''),
(5, 2, 15, 2, 9, '-16.12', 29, '8*', 180, 0, 'Running', 2, 'new_driver_44', ''),
(6, 2, 8, 3, 11, '-2:03.48', 29, '0', 165, 0, 'Running', 2, 'new_driver_83', ''),

Let me know if this is what you meant by raw values if not I can get some more data for you.


Just posting the solution here for completeness:

SELECT user.driver, race_stats.race_id, 
   SUM(race_stats.points) AS total_points "." 
FROM user, race_stats "." 
WHERE user.user_id=race_stats.user_id 
GROUP BY user.driver, race.race_id


Here's the query you want (formatted for readability):

SELECT
    u.driver,
    SUM(rs.points) AS total_points 
FROM user u
LEFT JOIN race_stats rs on rs.user_id = u.user_id
GROUP BY 1;

The advantage of using an outer join (ie LEFT JOIN) is that drivers who have no stats still get a row, but with null as total_points.

p.s. I don't know what the usage of "." in your query is all about, so I removed it.

0

精彩评论

暂无评论...
验证码 换一张
取 消