Php foreach loop inserts only part of records into mysql table

In my mysql database I get ONLY the records for id 26, 16, 17, 18, 19, 22, 23, 24. Why is that, is there any error in my code? I don;t have a clue, please help:(

<?
$connect = mysql_connect('localhost', 'dbname', 'pass');  
if (!$connect) { die('Could not connect: ' . mysql_error()); }
mysql_select_db("dbname") or die(mysql_error());

mysql_query("TRUNCATE TABLE anchors");

$blog_ids = array(
'anchor 1' => '1', 
'anchor 2' => '2', 
'anchor 3' => '3', 
'anchor 2' => '4',  
'anchor 2' => '5',  
'anchor 4' => '6',  
'anchor 5' => '7',  
'anchor 6' => '8', 
'anchor 7' => '9',  
'anchor 8' => '10', 
'anchor 9' => '13',
'anchor 10' => '14',
'anchor 11' => '16',
'anchor 12' => '17', 
'anchor 13' => '18', 
'anchor 14' => '20', 
'anchor 15' => '21', 
'anchor 16' => '22', 
'anchor 17' => '23', 
'anchor 18' => '24', 
'anchor 19' => '25', 
'anchor 20' => '26' 
);
foreach($blog_ids as $anchor => $blog_id){
$anchor_url = 'http://www.site.com';
mysql_query("INSERT INTO anchors (blog_id, anchor_url, anchor) VALUES ('$blog_id', '$anchor_url', '$anchor')");
} 

mysql_close($connect); 
?>

Ty very much, here is the table structure:

CREATE TABLE `anchors` (
 `id` int(11) NOT NULL auto_increment,
 `blog_id` text,
 `anchor_url` text,
 `anchor` text,
 PRIMARY KEY  (`id`),
 FULLTEXT KEY `posttitle` (`blog_id`,`a开发者_如何学编程nchor_url`,`anchor`)
) ENGINE=MyISAM AUTO_INCREMENT=10 DEFAULT CHARSET=utf8

---

Check whether the query actually can be executed.

if (mysql_query("INSERT INTO anchors (blog_id, anchor_url, anchor) VALUES ('$blog_id', '$anchor_url', '$anchor')") === FALSE) {
    echo 'failed: ' . mysql_error() . "\n";
}

Furthermore, what is the table structure like? SHOW CREATE TABLE anchors; will help you. If you have a unique or primary key set, the value really needs to be unique and duplicates fail with an error.

Edit: The problem is not within the script, but within the data. In order to have the data in PHP, the storage needs to be adjusted.

$blog_ids = array(
  array(
    'anchor' => 'anchor 1',
    'blog_id' => '1'
  ),
  array(
    'anchor' => 'anchor 2',
    'blog_id' => '2'
  ),
  …
);

foreach ($blog_ids as $blog_id_array) {
  $blog_id = $blog_id_array['blog_id'];
  $anchor = $blog_id_array['anchor'];
  $anchor_url = 'http://www.site.com';

  if (mysql_query("INSERT INTO anchors (blog_id, anchor_url, anchor) VALUES ('$blog_id', '$anchor_url', '$anchor')") === FALSE) {
    echo 'failed: ' . mysql_error() . "\n";
  }
}

---

This should probably be a comment, but it's a bit too long. If you run something like this and get errors, edit your original question to reflect what you've found. If you also post a comment on this answer, I can try to edit this answer to solve your problem.

For INSERT statements, mysql_query() returns FALSE on errors. You should check to see if any errors exist. I would edit your code to look more like this:

$result = mysql_query("INSERT INTO anchors (blog_id, anchor_url, anchor) VALUES ('$blog_id', '$anchor_url', '$anchor')");

if (!$result) {
    die('Invalid query: ' . mysql_error());
}

In deployment, I wouldn't necessarily die(), but log errors to some reporting mechanism or parse through mysql_error() and return a secure and friendly error message that doesn't reveal too much about the underlying database system or queries executed.