I have two arrays, and I have a complex condition like this: new_arr<0 and old_arr>0
I am using nonzero but I am getting an error. The code I have is this:
indices = nonzero(new_arr<0 and old_arr>0)
I tried:
indices = nonzero(new_arr<0) and nonzero(old_arr>0)
But it gave me incorrect results.
Is there any way around this? And is there a way to get the common indices from two nonzero statements. For example, if:
indices1 = nonzero(new_arr<0)
indices2 = nonzero(old_arr>0)
and these two indices would contain:
indices1 = array([0, 1, 3])
indices2 = array([2, 3, 4])
The correct result would be getting the common element from these two (in this case it would be the element 3). Something like this:
result = common(indices1, ind开发者_高级运维ices2)
Try indices = nonzero((new_arr < 0) & (old_arr > 0))
:
In [5]: import numpy as np
In [6]: old_arr = np.array([ 0,-1, 0,-1, 1, 1, 0, 1])
In [7]: new_arr = np.array([ 1, 1,-1,-1,-1,-1, 1, 1])
In [8]: np.nonzero((new_arr < 0) & (old_arr > 0))
Out[8]: (array([4, 5]),)
Try
indices = nonzero(logical_and(new < 0, old > 0))
(Thinking about it, my previous example wasn't all that useful if all it did was return nonzero(condition)
anyway.)
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