How do I create a class that can initialize C++ data types?

The title basically says it all. I mainly want to do this so that I can create an object (say, a custom string object) that can initialize the parameters of other functions in other APIs. Here's an example of me trying to get a custom integer class to work:

#include <iostream>
using namespace std;

class test
{
public:
    int member;
    test(int i) : member(i) {}

    friend int &operator=(int &i, test t);
};

int &operator=(int &i, test t)
{
   return (i = t.member);
}

int main()
{
    int i;
    test t = 90;

    cout << (i = t);
    return 0;
}

Unfortunately I receive an error saying that operator= needs to be a member function. I understand the C++ standard's goa开发者_Go百科l in preventing static and non-member overloads for the assignment operator from being implemented, but is there any other way to do this? Thanks for any help/suggestions!

---

This is not done with an assignment operator but with an overloaded typecast. This would make your main function work like expected:

#include <iostream>
using namespace std;

class test
{
public:
    int member;
    test(int i) : member(i) {}
    operator int() const {return member;}
};

int main()
{
    int i;
    test t = 90;

    cout << (i = t);
    return 0;
}

---

What you are trying to do needs an conversion operator

operator int() 
{
    return this->member;
}

---

For the class you are trying to write(containing only integer members), You do not need to overload the = operator.

= operator is one of the member functions that is generated by the compiler by default for every class. Caveat is, it does a simple bit by bit copy(shallow copy) of class members, since you have only integers it should be good enough for you.

You would need to overload the = operator if you had dynamically allocated pointers as member functions, because in that case a shallow copy of those pointers would result in all the objects containing a member pointer pointing to the same dynamic memory location & if one of the object finishes it lifetime, other objects are left with a dangling pointer.
As @Tony, aptly points in out comments Shallow copy is usually bad but not always. See his comments for a scenario.

If at all you want to overload the assignment operator check out the Copy and Swap Idiom to do it right way.

You should also check out the Rule of Three.

---

Try this:

class test
{
public:
    int member;
    test(int i) : member(i) {}

    operator int() {return this->member;}
};

int main(void)
{
    int i;
    test t = 90;

    cout << (i = t);
    return 0;
}

---

The assignment operator cannot be a friend function. The assignment operator can only be declared as a non-static member function. This is to ensure that it receives the L-value as its first operand. The same is true for the [], (), and -> operators. In your case, since int is an build-in type, you cannot use member function. You can implement operator int() to cast your user-defined type to int.