; 5 : int c=0;
mov DWORD PTR _c$[ebp], 0
I don't understand the syntax, why 开发者_运维问答c is referenced without bracket and why add [ebp] ?
EBP is the frame pointer. Since c is a local variable or argument, c is an offset relative to the frame pointer.
![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif)
加载中,请稍侯......
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