Django: add model fields to list_display and display related values per entry

I have the following model definitions, see below.

models.py:

class Userstatus(开发者_高级运维models.Model):
    label = models.CharField(...)
    description = models.CharField(...)


class Foo(models.Model):
    title = models.CharField(...)
    visibility = models.ManyToManyField(Userstatus)

admin.py:

class FooAdmin(ModelAdmin):
    list_display = ('id', 'title', )

admin.site.register(Foo, FooAdmin)

In the admin list view of "Foo" via FooAdmin the list_display list should include the "label"s from Userstatus so a column for each label will appear. I could create and call a method that creates the list for list_display.

But then no properties or callables actually exist that would allow me to return let's say a boolean for each label column, based on the visibility-many-to-many field.

What are my options? Should I try to intercept a callable or attribute request to Foo and create a boolean result on the fly? (Hitting the DB too often or making the columns sortable is another problem, but first things first).

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Django documentation says ...

ManyToManyField fields aren't supported, because that would entail executing a separate SQL statement for each row in the table. If you want to do this nonetheless, give your model a custom method, and add that method's name to list_display. (See below for more on custom methods in list_display.)

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Are you sure you want Userstatus to be a database table and not just a list of a few statuses that could be accessed through a "choices" tuple?