public byte[] method(int var1)
{
if(var1 == ~L.length) //<- this
return a(i1, 0, false);
}
how would I go upon fixing
if(var1 == ~L.length)
to remove the ~
must I change ==
to !=
?
if(var1 != L.length)
Thanks this is probably the last question of this type.
ps.> Thanks for helping me out with the previous ones like
~(-1 + var1) < -1
to var1 > 1
~(var1 & 0x22) != -1
to (var1 & 0x22) != 0
~var1 < ~var2
to var1 &开发者_如何学Pythongt; var2
As I told you before, you can replace ~x
with -x - 1
So, if(var1 == ~L.length)
is equivalent to if(var1 == -L.length - 1)
If it's trying to do 2's complement tricks again:
-var1 == L.length + 1
or
var1 + 1 == -L.length
(Basically use the fact that ~x == -(x+1) == -x - 1
)
Another way to rewrite it is:
var1 ^ L.length == -1
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