Using the following command
gcc -c -Wall -Wextra -pedantic -ansi -std=c99 -fstack-protector-all -fstack-check -O3 root.c -o rootTESTOBJECT
I get the compiler warning root.h:76:22: warning: ISO C does not permit named variadic macros
72 #ifdef Debug
73 #inclu开发者_开发技巧de <stdio.h>
74 #define crumb(phrase0...) printf(phrase0)
75 #else
76 #define crumb(phrase0...)
77 #endif
I believe the option -ansi -std=c99 allows the use of variadic macros, it does according to the docs anyway...
I have tried editing line 76 to
76 #define crumb(phrase0...) printf("")
to see if this fixed the warning but with no joy.
the compiler verion is Apple's gcc, version 4.2.1 I'm not sure if I need be too concerned by this but I really don't like warnings. What flag's am I missing ?
#define crumb(phrase0...) <whatever>
is giving a name (phrase0
) to the variable arguments (...
).
This is a GCC extension.
C99 does define a way of passing variable arguments to macros (see §6.10.3/12 and §6.10.3.1/2): the variable arguments are unnamed
on the left-hand side of the definitions (i.e. just ...
), and referenced on the right-hand side as __VA_ARGS__
, like this:
#define crumb(...) printf(__VA_ARGS__)
(By the way, your gcc
arguments should not include both -ansi
and -std=c99
: -ansi
specifies the earlier C standard (known variously as ANSI C, C89 or C90); the combination of both options only happens to select C99 in this case because -std=c99
appears after -ansi
in the argument list, and the last one wins.)
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