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Popen.stdin with multithreading problem, does not work

开发者 https://www.devze.com 2023-03-21 13:57 出处:网络
I am trying to run a shell from my python program. I have used a mltithreaded approach where an input from user is accepted and should be executed via the shell.

I am trying to run a shell from my python program. I have used a mltithreaded approach where an input from user is accepted and should be executed via the shell.

Everything seems right, except that the program execution just doesn't take place beyond stdin.

I am not sure if there is something wrong with the way I have used Popen.stdin.

So please help on what is wrong here.

from subprocess import Popen,PIPE
import shlex
import threading
from Queue import Queue


class MyThread(threading.Thread):
    def __init__(self,func,args):
        threading.Thread.__init__(self)
        self.func=func
        self.args=args

    def run(self):
        apply(self.func,self.args)

开发者_如何学编程

def bash(command,output):
    commandList=shlex.split('python test.py')   
    process=Popen(commandList,stdout=PIPE,stdin=PIPE,stderr=PIPE,shell=True)
    print process.stdout.readlines()
    while (process.pole()==None):
        #commandList=shlex.split(command.get(1))
        print 'bash'
        process.stdin.write(command.get(1))
        process.stdin.flush()
        output.put(process.stdout.readlines(),1)
        process.stdout.flush()



def communicate(command,output):
    while True:
        command.put(raw_input('enter command>'))
        print 'communicate'
        print output.get(1)



funcs=[bash,communicate]
nfuncs=len(funcs)    

def main():

    command=Queue(1)
    output=Queue(1)
    threads=[]

    for i in range(nfuncs):
        t=MyThread(funcs[i],(command,output))
        threads.append(t)

    for i in range(nfuncs):
        threads[i].start()

    for i in range(nfuncs):
        threads[i].join()

    print 'successful'       

if __name__=='__main__':
    main()

I have given the output below.

karthik@ubuntu:~/TerminalChatBot/test$ python threadTerminal.py
enter command>ls
communicate

After this there is no execution. I can't even use ctrl+c to stop the python script. It just hangs.

NOTE: the thread communicate needs to be there as we need to integrate this code with the bigger module.


Minor things:

It's process.poll() not process.pole().

Instead of

 for i in range(nfuncs):
    t=MyThread(funcs[i],(command,output))
    threads.append(t)

do

 for func in nfuncs:
    t=MyThread(func,(command,output))
    threads.append(t)

Now, why are you running python test.py? Don't you want to run ls communicate in a shell, in which case you should be doing something like:

def bash(command,output):
    process=Popen('bash',stdout=PIPE,stdin=PIPE,stderr=PIPE,shell=True)
    print process.stdout.readlines()
    # I don't really understand what's going on here
    while (process.pole()==None):
        print 'bash'
        process.stdin.write(command.get(1))
        process.stdin.flush()
        output.put(process.stdout.readlines(),1)
        process.stdout.flush()


could it be that it keeps hanging on process.stdout.readlines()? Perhaps no line ending can be found. Try stdout.read(1) to read one character and see what happens.

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