Casting primitive data types

public class TestEmployee {
    public static void main(String args[]) { 
          byte b=(byte)1*200;
          System.out.println(b);
       }
   }

I have written above simple code. But I am getting folowing error "Possible loss of precision"

As of my knowledge, when we perform integer calculations , the operands are converted to int and then the calculation in performed. And final result is in int. Now as the range of byte data type is (-128 to 127) the above calculatio开发者_StackOverflow社区ns falls out of range of byte. So I downcast it to byte. Then why I am getting the error.

Please help and correct my concepts of casting..

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You are casting the 1 to a byte, not the result of 1*200. So you want to use

byte b = (byte)(1*200);

in this case.

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your code should go like this....just missing the brackets before the multiplication operation otherwise only 1 will be downcast and 200 remains as integer

public class TestEmployee {
public static void main(String args[]) 
{ byte b=(byte) ( 1 * 200); 
  System.out.println(b);
} 
}

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You haven't put 1 * 200 in brackets. It should be byte b = (byte)(1 * 200).

Otherwise you do byte b = 200 which is an int and you get an error.

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You are missing the parenthesis () while downcasting.
Change like this,

   byte b=(byte)(1*200);

When you write like this,

   byte b=(byte)1*200;
                 ^
   `compilation error :  possible loss of precision`

It is because it tries to convert an int : 200 to byte which will result in compilation error.