How to find the largest number in a particular column of MS access table? I'm using C#.
I'm not able to make the logic for this. I was doing this:
int i, lastID;
int y = 0;
int lastRow = DS.Tables[0].Rows.Count;
for (i = 0; i > -1; i++)
{
i = Convert.ToInt32(DS.Tables[0].Rows[i]["id"].ToString());
lastID = (y > i) ? y : i;
if (i > lastRow)
{
lastID++;
empIdLabel.Text = lastID.ToString();
}
}
I'm fusse开发者_高级运维d !!!!
Barring an obvious reason why not, you should use SQL: SELECT MAX(id) FROM . . .
.
You can do this with an OLEDB connection:
OleDbConnection connection = new OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;data source=blahblah.mdb"));
connection.Open();
OleDbCommand maxCommand = new OleDbCommand("SELECT max(id) from TABLENAME", connection);
Int32 max = (Int32)maxCommand.ExecuteScalar();
Note that I'm on a Linux machine, so I haven't tested the above, but it should be pretty close from what I remember of C#.
you can use SQL for this purpose
select max(id) from tablename
It is recomended to do it in query rather than in code.
The query could be
Select Max(ColName) From TableName;
String cs = @"Provider=Microsoft.ACE.OLEDB.12.0;Data
Source=databasepath\databasename.mdb";
OleDbConnection con = new OleDbConnection(cs);
con.Open();
OleDbCommand com = new OleDbCommand("select Max(id) as ID from tablename",
con);
com.CommandType = CommandType.Text;
OleDbDataReader r = com.ExecuteReader();
r.Read();
if (r["ID"].ToString() != "")
{
temp = int.Parse(r["ID"].ToString()) + 1;
}
else
{
temp = 1;
}
textBox1.Text = temp.ToString();
r.Close();
con.Close();
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