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How can I grep through an array, while filtering out matches?

开发者 https://www.devze.com 2023-03-21 00:13 出处:网络
Is there a quick and easy way to grep th开发者_JS百科rough an array finding the elements satisfying some test and remove these from the original array?

Is there a quick and easy way to grep th开发者_JS百科rough an array finding the elements satisfying some test and remove these from the original array?

For example I would like

@a = (1, 7, 6, 3, 8, 4);
@b = grep_filter { $_ > 5 } @a;

# now @b = (7, 6, 8)
# and @a = (1, 3, 4)

In other words, I want to split an array into two arrays: those which match and those which do not match a certain condition.


Know your libraries, mang.

use List::MoreUtils qw(part);
part { $_>5 } (1, 7, 6, 3, 8, 4)

returns

(
    [1, 3, 4],
    [7, 6, 8],
)


my @a = (1, 7, 6, 3, 8, 4);
my (@b, @c);    

push @{ $_ > 5 ? \@b : \@c }, $_ for @a;


Using libraries is good, but for completeness, here is the function as specified in the question:

sub grep_filter (&\@) {
    my ($code, $src) = @_;
    my ($i, @ret) = 0;
    local *_;
    while ($i < @$src) {
        *_ = \$$src[$i];
        &$code
            ? push @ret, splice @$src, $i, 1
            : $i++
    }
    @ret
}

my @a = (1, 7, 6, 3, 8, 4);
my @b = grep_filter {$_ > 5} @a;

say "@a"; # 1 3 4
say "@b"; # 7 6 8


Is this what you want?

@a = (1, 7, 6, 3, 8, 4);
@b = grep_filter { $_ > 5 } @a;
@a = grep_filter { $_ < 5 } @a;

do another grep with your condition negated.

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