I am a beginner with Ruby. So I searched how reverse a matrix
1, 2, 3, 4 8, 9, 10, 11
4, 5, 6, 7 =>开发者_Go百科; 4, 5, 6, 7
8, 9, 10, 11 1, 2, 3, 4
I have tried:
require 'matrix'
m = Matrix[ [1,2,3,4],[4,5,6,7], [8,9,10,11] ]
m_rev = Matrix.build(m.row_size, m.column_size){|row|
m.row_size.downto(0){|i|
row = m.row(i)
}
}
Try: Matrix[*m.to_a.reverse]
:
m = Matrix[ [1,2,3,4], [5,6,7,8], [9,10,11,12] ]
#=> Matrix[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
r = Matrix[*m.to_a.reverse]
#=> Matrix[[9, 10, 11, 12], [5, 6, 7, 8], [1, 2, 3, 4]]
Do not miss the *
.
You can do something like:
m_rev = Matrix.rows m.to_a.reverse
You were on the right track, except that Matrix.build
iterates over both rows and columns:
m_rev = Matrix.build(m.row_size, m.column_size){|row, column|
m[-row-1, column]
}
Simpler and faster:
m_rev = Matrix.rows(m.to_a.reverse)
# or
m_rev = Matrix[*m.to_a.reverse]
精彩评论