Javascript function access

I have a block of code in $(function() { function parseData(){...} )};

I also have a function declared outside of the ready block. This is outside since I hook it up in codebehind ie ddlCategories.Attributes.Add("onchange", "getDataFields()");

From the getDataFields function, I need to call parseData but it does not seem to find it.

How do I access my parseData() which is in my ready block, from outside of the ready block?

(sorry if some of terminology is off - I am now to JS开发者_开发问答)

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Any reason parseData() has to be in the ready block? Why not just make it a top level function:

<script type="text/javascript">

function parseData() { ... }

$(document).ready( function() {
   ddl.Categories.....
}
<script>

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Just define it outside your ready block. It's currently inaccessible due to the scope of the function.

Definitions can always safely go outside $(function() { ... }) blocks because nothing is executed.

$(function() { ... });

function parseData() { ... }

However, you seem to have a syntax error: )}; should be });.

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Declare your parseData function outside of the self-executing $(function(){}); block.

var parseData = function () { ... };

$(function() { ... });

If there are things you need to reference inside the self-executing function, then declare the function globally but define it inside the self-executing function:

var parseData;

$(function() { parseData = function () { ... }; });

As an aside, declaring functions or variables globally is a bad idea.

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You should declare the function outside the $(function() { ... }) callback.